// StartMathJax Script window.MathJax = {loader: {load: [ 'input/asciimath', 'ui/lazy', 'output/chtml', 'ui/menu']} }; (function() { var script = document.createElement('script'); script.src = "https://cdn.jsdelivr.net/npm/mathjax@3/es5/startup.js"; script.async = true; document.head.appendChild(script); })(); ---------- (Different files) ---------- // UpdateTypeset Script config = { attributes: true, childList: true, subtree: true }; // Callback function to execute when mutations are observed callback = (mutationList, observer) => { for (mutation of mutationList) { if (mutation.type === 'childList') { console.log('A child node has been added or removed.'); MathJax.typeset(); } else if (mutation.type === 'attributes') { console.log(`The ${mutation.attributeName} attribute was modified.`); } } }; // Create an observer instance linked to the callback function observer = new MutationObserver(callback); document.onreadystatechange = () => { if (document.readyState === 'complete') { console.log("Loaded fully according to readyState") targetNode = document.getElementById('content-wrapper') console.log(targetNode) // Start observing the target node for configured mutations observer.observe(targetNode, config); } }
 

GCSE Trial & Improvement Questions - easy when you know how.

Updated: Apr 18



In ‘trial & improvement’ questions, there are steps you can use to guarantee full marks. The idea is to gradually zero in on a reasonable answer. A methodical approach is needed to gain a relatively easy 4+ marks.


Let’s look at an example…


Using the following equation, find a solution for x using a trial and improvement method



Give your answer to 1 decimal place.


To maximise your marks, you need to show step -by-step reasoning.

First, draw a table like this…



For x values, you are looking for two consecutive numbers between which the target number lies... We'll try x = 2 and 3